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-16x^2+12.8x+3.2=0
a = -16; b = 12.8; c = +3.2;
Δ = b2-4ac
Δ = 12.82-4·(-16)·3.2
Δ = 368.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12.8)-\sqrt{368.64}}{2*-16}=\frac{-12.8-\sqrt{368.64}}{-32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12.8)+\sqrt{368.64}}{2*-16}=\frac{-12.8+\sqrt{368.64}}{-32} $
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